zip_open 0.2.0

zip_open allows you to open a file from a nested zip file archive.

If you use static file like as 'data.zip' and open this from your python code, Your program will become like open(os.path.join(os.path.dirname(__file__), 'data.zip')). But if your packages are packed into packages.zip file (zipped-egg, or cases to gather in one file on Google App Engine matter), your cord doesn't work fine.

In this situation, the file path of data.zip becomes /path/to/packages.zip/data.zip, then your program can't open the data.zip file.

zip_open package solves this problem.

Usage sample1: open the file from zip file

packages1.zip is:

packages1.zip
 + file1.txt

Open file1.txt:

>>> from zip_open import zopen
>>> fobj = zopen('packages1.zip/file1.txt')
>>> data = fobj.read()
>>> print data
I am file1.txt, ok.

This code sample equivalent to below code:

>>> from zipfile import ZipFile
>>> zipobj = ZipFile('packages1.zip')
>>> data = zipobj.read('file1.txt')
>>> print data
I am file1.txt, ok.

Usage sample2: open the file from nested zip file

packages2.zip is:

packages2.zip
 + data2.zip
 + file2.txt

Open file2.txt:

>>> from zip_open import zopen
>>> fobj = zopen('packages2.zip/data2.zip/file2.txt')
>>> print fobj.read()
I am file2.txt, ok.

Usage sample3: open the file included in package oneself

packages3.zip is:

packages3.zip
 + foo.py
 + file1.txt
 + data3.zip
 + file3.txt

foo.py:

import os
from zip_open import zopen

def loader(filename):
 fobj = zopen(os.path.join(os.path.dirname(__file__), filename))
 return fobj

execute loader() from interactive shell:

>>> import sys
>>> sys.path.insert(0, 'packages3.zip')
>>> import foo
>>> fobj = foo.loader('file1.txt')
>>> print fobj.read()
I am file1.txt, ok.
>>> fobj = foo.loader('data3.zip/file3.txt')
>>> print fobj.read()
I am file3.txt, ok.


Product's homepage

Requirements:

· Python

What's New in This Release: [ read full changelog ]

· Change license from PSL to Apache License 2.0
· Add feature: open from file-like-object.